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Fixed BUG#9073: Able to declare two handlers for same condition in same scope

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This commit is contained in:
pem@mysql.comhem.se
2005-04-08 19:58:04 +02:00
parent e6d72f1c48
commit 2038ced40c
6 changed files with 170 additions and 7 deletions
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41
mysql-test/r/sp-error.result
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@@ -526,4 +526,45 @@ delete from t1|
call bug7299()|
ERROR 02000: No data to FETCH
drop procedure bug7299|
create procedure bug9073()
begin
declare continue handler for sqlexception select 1;
declare continue handler for sqlexception select 2;
end|
ERROR 42000: Duplicate handler declared in the same block
create procedure bug9073()
begin
declare condname1 condition for 1234;
declare continue handler for condname1 select 1;
declare exit handler for condname1 select 2;
end|
ERROR 42000: Duplicate handler declared in the same block
create procedure bug9073()
begin
declare condname1 condition for sqlstate '42000';
declare condname2 condition for sqlstate '42000';
declare exit handler for condname1 select 1;
declare continue handler for condname2 select 2;
end|
ERROR 42000: Duplicate handler declared in the same block
create procedure bug9073()
begin
declare condname1 condition for sqlstate '42000';
declare exit handler for condname1 select 1;
declare exit handler for sqlstate '42000' select 2;
end|
ERROR 42000: Duplicate handler declared in the same block
drop procedure if exists bug9073|
create procedure bug9073()
begin
declare condname1 condition for sqlstate '42000';
declare continue handler for condname1 select 1;
begin
declare exit handler for sqlstate '42000' select 2;
begin
declare continue handler for sqlstate '42000' select 3;
end;
end;
end|
drop procedure bug9073|
drop table t1|