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merge of 5.0-opt -> 5.1-opt

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gkodinov/kgeorge@macbook.gmz
2007-01-24 15:55:16 +02:00
parent 17a0207ece
commit 13238b0e3d
7 changed files with 90 additions and 114 deletions
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70
mysql-test/t/func_in.test
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@@ -254,42 +254,44 @@ select some_id from t1 where some_id not in(-4,-1,-4);
select some_id from t1 where some_id not in(-4,-1,3423534,2342342);
drop table t1;
# TODO:Disabled until re-resolution of bug #20420 for 5.1.
# Results must be the same as in 5.0
##
## BUG#20420: optimizer reports wrong keys on left join with IN
##
#CREATE TABLE t1 (a int, b int, PRIMARY KEY (a));
#INSERT INTO t1 VALUES (1,1),(2,1),(3,1),(4,1),(5,1),(6,1);
#
# BUG#20420: optimizer reports wrong keys on left join with IN
#CREATE TABLE t2 (a int, b int, PRIMARY KEY (a));
#INSERT INTO t2 VALUES (3,2),(4,2),(100,100),(101,201),(102,102);
#
CREATE TABLE t1 (a int, b int, PRIMARY KEY (a));
INSERT INTO t1 VALUES (1,1),(2,1),(3,1),(4,1),(5,1),(6,1);
CREATE TABLE t2 (a int, b int, PRIMARY KEY (a));
INSERT INTO t2 VALUES (3,2),(4,2);
CREATE TABLE t3 (a int PRIMARY KEY);
INSERT INTO t3 VALUES (1),(2),(3),(4);
CREATE TABLE t4 (a int PRIMARY KEY);
INSERT INTO t4 VALUES (1),(2);
EXPLAIN SELECT STRAIGHT_JOIN * FROM t3
JOIN t1 ON t3.a=t1.a
JOIN t2 ON t3.a=t2.a
JOIN t4 WHERE t4.a IN (t1.b, t2.b);
SELECT STRAIGHT_JOIN * FROM t3
JOIN t1 ON t3.a=t1.a
JOIN t2 ON t3.a=t2.a
JOIN t4 WHERE t4.a IN (t1.b, t2.b);
EXPLAIN SELECT STRAIGHT_JOIN
(SELECT SUM(t4.a) FROM t4 WHERE t4.a IN (t1.b, t2.b))
FROM t3, t1, t2
WHERE t3.a=t1.a AND t3.a=t2.a;
SELECT STRAIGHT_JOIN
(SELECT SUM(t4.a) FROM t4 WHERE t4.a IN (t1.b, t2.b))
FROM t3, t1, t2
WHERE t3.a=t1.a AND t3.a=t2.a;
DROP TABLE t1,t2,t3,t4;
#CREATE TABLE t3 (a int PRIMARY KEY);
#INSERT INTO t3 VALUES (1),(2),(3),(4);
#
#CREATE TABLE t4 (a int PRIMARY KEY,b int);
#INSERT INTO t4 VALUES (1,1),(2,2),(1000,1000),(1001,1001),(1002,1002),(1003,1003),(1004,1004);
#
#EXPLAIN SELECT STRAIGHT_JOIN * FROM t3
# JOIN t1 ON t3.a=t1.a
# JOIN t2 ON t3.a=t2.a
# JOIN t4 WHERE t4.a IN (t1.b, t2.b);
#
#SELECT STRAIGHT_JOIN * FROM t3
# JOIN t1 ON t3.a=t1.a
# JOIN t2 ON t3.a=t2.a
# JOIN t4 WHERE t4.a IN (t1.b, t2.b);
#
#EXPLAIN SELECT STRAIGHT_JOIN
# (SELECT SUM(t4.a) FROM t4 WHERE t4.a IN (t1.b, t2.b))
# FROM t3, t1, t2
# WHERE t3.a=t1.a AND t3.a=t2.a;
#
#SELECT STRAIGHT_JOIN
# (SELECT SUM(t4.a) FROM t4 WHERE t4.a IN (t1.b, t2.b))
# FROM t3, t1, t2
# WHERE t3.a=t1.a AND t3.a=t2.a;
#
#DROP TABLE t1,t2,t3,t4;
--echo End of 5.0 tests