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New way to fix BUG#19243 "wrong LAST_INSERT_ID() after ON DUPLICATE KEY UPDATE".

This bug report was two problems:
1) LAST_INSERT_ID() returns a value which does not exist in the table
2) the reporter would want it to return the autoinc id of the updated
row.
1) is a real bug, 2) is a feature request.
In July I implemented 2) in 5.1 (which automatically fixes 1).
This has not yet been documented or released, so is changeable.
Precisely, recently Paul and a user found an easy workaround to give
2), which works in 4.1-5.0-5.1. So I can revert my code for 2),
because it's not needed, that's what I do here;
we forget about 2) (we will document the workaround).
But when I revert my code for 2), 1) comes back. We solve 1) by saying
that if INSERT ON DUPLICATE KEY UPDATE updates a row, it's like a
regular UPDATE: LAST_INSERT_ID() should not be affected (instead of
returning a non-existent value).
So note: no behaviour change compared to the last released 5.1; just
a bugfix for 1).
This commit is contained in:
guilhem@gbichot3.local
2006-09-06 12:50:42 +02:00
parent 8e2ca1564a
commit 04284f8c10
3 changed files with 51 additions and 15 deletions

View File

@ -432,22 +432,44 @@ ifnull( c,
0 ) + 1;
select last_insert_id();
last_insert_id()
1
2
select last_insert_id(0);
last_insert_id(0)
0
insert into t2 ( a ) values ( 6 ) on duplicate key update c =
ifnull( c,
0 ) + 1;
select last_insert_id();
last_insert_id()
0
select * from t2;
k a c
1 6 1
1 6 2
2 7 NULL
insert ignore into t2 values (null,6,1),(10,8,1);
select last_insert_id();
last_insert_id()
1
0
insert ignore into t2 values (null,6,1),(null,8,1),(null,15,1),(null,20,1);
select last_insert_id();
last_insert_id()
11
select * from t2;
k a c
1 6 1
1 6 2
2 7 NULL
10 8 1
11 15 1
12 20 1
insert into t2 ( a ) values ( 6 ) on duplicate key update c =
ifnull( c,
0 ) + 1, k=last_insert_id(k);
select last_insert_id();
last_insert_id()
1
select * from t2;
k a c
1 6 3
2 7 NULL
10 8 1
11 15 1