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fixed argument passing (#2209)

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Using espota.py as a module by calling espota.main(args) was not working because the args given to main were not being passed into parser.parse_args().  I fixed this by having main pass args to the parser function, which in turn passes them to the parser object's parse_args() function.
This commit is contained in:
mmarchese1
2016-07-05 21:59:23 -05:00
committed by Ivan Grokhotkov
parent 4217e49b54
commit 24f84664e7
1 changed files with 4 additions and 4 deletions
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8
tools/espota.py
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@@ -21,7 +21,7 @@
# Changes # Changes
# 2015-11-09: # 2015-11-09:
# - Added digest authentication # - Added digest authentication
# - Enchanced error tracking and reporting # - Enhanced error tracking and reporting
# #
# Changes # Changes
# 2016-01-03: # 2016-01-03:
@@ -199,7 +199,7 @@ def serve(remoteAddr, localAddr, remotePort, localPort, password, filename, comm
# end serve # end serve
def parser(): def parser(unparsed_args):
parser = optparse.OptionParser( parser = optparse.OptionParser(
usage = "%prog [options]", usage = "%prog [options]",
description = "Transmit image over the air to the esp8266 module with OTA support." description = "Transmit image over the air to the esp8266 module with OTA support."
@@ -275,7 +275,7 @@ def parser():
) )
parser.add_option_group(group) parser.add_option_group(group)
(options, args) = parser.parse_args() (options, args) = parser.parse_args(unparsed_args)
return options return options
# end parser # end parser
@@ -283,7 +283,7 @@ def parser():
def main(args): def main(args):
# get options # get options
options = parser() options = parser(args)
# adapt log level # adapt log level
loglevel = logging.WARNING loglevel = logging.WARNING